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  #16 (permalink)  
Old 10-27-2006, 06:49 AM
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newby Bob

I couldn't help but make a comment on the discussion, for those interested in some graphic footage of a tyre under deflection in race conditions, get a hold of Bathurst 2006, V8 Supercars Australia, where a camera was mounted under the Ford of winner Craig Lowndes. Bathurst is a twisty, mountain circuit where an annual pilgrimage takes place in October for the 1,000 Km event, which is renowned as a heart breaker. My experience is limited compared to most who have commented herein, however for what it's worth, there are as many variables as types of use, eg drag racing, street and circuit racing pressures all vary, especially with the width of rim and vehicle weight. Loaded radius is a starting point, low profile tyres require much higher operating pressures than is the norm, 38-42 psi is not unusual on a street driver. A particular tyre size will require different pressures under different conditions, wheel width, vehicle weight/load, operating conditions and in the case of the above mentioned race clip, driving conditions, operating temps, etc. Regards, Bob

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  #17 (permalink)  
Old 10-27-2006, 11:23 AM
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Interesting web vid.....

http://www.dump.com/rdzte/
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Old 10-27-2006, 01:06 PM
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Just to avoid confusion among the young readers who follow these threads:

Quote:
Originally Posted by sabino56
The tangential acceleration is radius x angular accel in rad^2/sec.
Should be rad/sec^2

Quote:
Originally Posted by sabino56
The radial accel, that is the acceleration required to keep it moving in a circle is radius x angular accel squared.
Should be radius x angular velocity squared.

(Yes, I realize these were careless typos, sabino56, and I probably should have sent you a PM and given you a chance to make the corrections yourself.)
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Old 10-27-2006, 01:22 PM
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Easiest way to be dead on every time is to dump the mechanical speed-o and go GPS speed-o!!!! About as accurate as you can get, except when in tunnels and underground parking garages! LOL


How about we talk about the forward speed of the top of the tire at....say...60mph? Any takers? LOL
Mark
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Old 10-27-2006, 09:19 PM
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Quote:
Originally Posted by BillyShope
Just to avoid confusion among the young readers who follow these threads:



Should be rad/sec^2



Should be radius x angular velocity squared.

(Yes, I realize these were careless typos, sabino56, and I probably should have sent you a PM and given you a chance to make the corrections yourself.)
Thanks! you are correct. I appreciate you catching the errors.
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