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Old 02-07-2004, 03:00 PM
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Mechanical water pump drive ratio

Guys, I don't know how to figure out the water pump drive ratio(under or over) I have on my 23 Bucket. I would appreciate your taking me by the hand all the way through on this one or send me to a website that I could use. Much thanks for any help. NOSLO23

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Old 02-07-2004, 04:13 PM
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Just measure the pulley diameters then do math. Math part is always the same just plug in whatever pulley diameters youre going to use.


Example

Engine rpm 2500

Crank pulley 7"

Water pump 6"

Drive divided by driven = rpm ratio (underdriven or overdriven)

7 / 6 = 1.16

1.16 x 2500 = 2900 water pump RPM
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Old 02-08-2004, 12:23 AM
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Greg, thanks for the primer. If you don't mind, a couple more questions, then I think we can put this to bed. In your example, you show the crank as a 7" dia., is this measurement as simple as the distance across the face of the pulley or is it measured at the bottom of the "v" groove on one side of the pulley to the bottom of the "v" groove on the other side? The last is, I've read you should not over drive a pump by more than 30%, may I assume in the example the water pump is being over driven by 16% (7/6 = 1.16)? NOSLO23
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