
07212013 09:01 AM  
64SS327 
I worked part time at a GoodYear dealership about ten years ago. We used the Equal brand balancing compound and never had any complaints. I seem to remember something about not using it in the steer tires on semis but it's been so long I don't remember. I used Equal in both my 77 Bronco with 16/38.515 Super Swampers and 78 GMC with 31's with good results. I put it in when I mounted the tires so I can't say it made the ride any better. I just never had any issues with it in my tires. 

07202013 03:20 PM  
ForceFed86 
Went 147 mph on my bead balanced tires this weekend...must be magic! 

07132013 08:20 PM  
Too Many Projects  I recently retired from trucking after 28 years as an owner/operator and for the last 12 years have used balancing beads exclusively in my semi tires. They are the ONLY balancing method that eliminated cupping and flat spots. The Peterbilt I sold 3 weeks ago had 1.2 million miles on it of which I drove it 800,000 miles with beads in the tires. Since I also do all my own tire work, I moved the beads from a worn tire to the new, saving the cost of bead replacement too. Very cost effective, accurate balancing.  
07062013 06:46 PM  
strobe 
Quote:
in answer to your 1st point ; it is an invalid entry ie it is not relevant. the compound was in the tire regardless of who put it there. I know because I saw the tire removed and emptied of the beads. point 2 half valid in that I dont know the exact weight but I do know that they are a commercially available brand caveman point ; I understand the plastic bottle physics perfectly rather you jump the gun in assuming I don't and if you are suggesting that it is in anyway capable of being a control experiment for a tire at 137 then ... Finally the video is not real world its a constant shape plastic bottle as opposed to a rubber tire which every turn has a flat area at the contact with the road and in some conditions is subject to huge external accelerations which are otherwise known as bumps anyway its all academic because I had a truck that was shaking itself to bits and now the beads are out its silky smooth so I need no further evidence,perhaps the truth lies in the middle ie it works in some applications but not in others after all we are in very different fields but make no mistake it doesn't work in mine anyway don't take it all too personally its only a tiny bit of a very big picture 

07032013 09:17 AM  
o1marc  Sorry, didn't read all the posts here. I have had nothing but positive results from DynaBeads.  
07032013 09:07 AM  
ForceFed86 
Quote:
I didn't use dyna beads. I used 4.5oz of airsoft pellets in each tire. Without some sort of bead lock it's very typical for a tire to slip on the rim when drag racing. So the typical spin balance doesn't work well for us. Myself and and many others at our track use the airsoft pellets and they work great. Honestly I've "spin balanced" a few slicks/drag radials and they didn't perform that badly. A little wobble on the big end of the track is normal. As I had said back in my original post on this thread I think one of the slicks were just beyond what a standard balance could compensate for. I was very suprised the beads not only "fixed" the issue, but the car acted better than ever before at speed. My next step was just to junk both slicks so a $4 airsoft pellet experiment was worth it IMO. 

07032013 08:33 AM  
o1marc 
Quote:
I'm surprised with your results at 137mph and a big ***slick. I assume you are drag racing? The Dyna Beads instructions highly recommends they not be used in racing situations especially drag racing. 

07032013 05:53 AM  
ForceFed86 
Quote:
1.) You didn't put the "compound" material in your tires. 2.) You don't know what "compound" was used or how much? Yet you can claim that all tire balance beads are total crap and can't work properly when like a million people have been using it for decades and claim it works. I personally have used them and they worked great in my application. It's very simple physics and works just fine in a "real world setting". Ie smooth as glass at 137mph in a big *** slick. Did you look at the video above? A caveman could understand it. The fact that you cant scares me a bit. 

07032013 01:58 AM  
strobe 
balancing beads/compound My experience backs up what forestrytodd says ie this concept is junk It was put in the front tyres of my Scania 124 without me knowing and immediately on long haul work(smooth road constant speeds) at 56mph there was a wobble on the front axle that would come and go at regular intervals(as the compound aggregated itself into one place and then would spread out again and the wobble would go away before repeating the cycle again . . .and again and again and again until it drove me so mad wondering what the hell could be doing this. I finally went to a proper tyre shop who asked if it had compound in the tyres at which point I said "has it got WHAT!" so after taking the crap out they balanced the wheels the proper way with weights and it's been silk ever since DONT GO NEAR THE STUFF anybody with high school physics will know its it cant work in a real world setting (on paper maybe) 

10022012 12:18 PM  
ForceFed86 
If old Bill down at the piggly wiggly says it don't work.... Common sense and first hand experiance with the product tells me otherwise. Still using this stuff in my slicks, works great! 

10022012 11:40 AM  
o1marc  I can't imagine why a guy who sells expensive machines would laugh at a $30 solution that work now and has been used for decades. Dump truck guys would put 34 golf balls in their tires to do the exact same thing BITD.  
05172012 08:00 AM  
bentwings  I hang out in a large truck shop and every over the road truck that I see has massive balancers at each wheel. The shop guys claim they really work. 90100k miles on big truck tires must mean something. They change 100 tires a day sometimes on this fleet.  
05172012 01:08 AM  
DesignoSLK 
Quote:
xxllmm4  I assume your WRX tires are low profile? I have 225/40ZR18s on my MB SLK230 and am having a heck of a time getting balanced. Driving the Autobahn daily, I need rock solid balancing. Are you still happy with the results of these? 

02132012 01:50 PM  
JusttCruzn 
Balance Beads WOW...very nice Old Fool. I'm so glad there are folks like you out there that can understand that stuff. As for me?... I just know what I feel in the steering wheel and the seat of my pants ... a smoooooth ride I do not have to know exactly how a wrist watch works. I just know that it does and I use it EVERY day. 

02132012 01:24 PM  
Old Fool 
Take a baton, it has a heavy and light end. place it on a finger. When it is balanced the light end is farther from your finger and the heavy end is closer. That demonstrates the center of Rotational balance, not the physical center of the baton. The beads will travel to the greatest distance from the Rotational balance center which will then move the center of rotational balance closer to the center of rotation. The beads acting as a fluid will continue to adjust as long as a rotational force greater than their individual mass is present. That is a simple explanation of how it works. Someone said their memory of physics say it won't work, After some Googling I came across the physics formula that explains why it does work: Think about it like this: x = \alpha \cos \frac{s}{\alpha} \ ; y=\alpha \sin\frac{s}{\alpha} \ . Then: x^2+y^2 = \alpha^2 \ , which can be recognized as a circular path around the origin with radius α. The position s = 0 corresponds to [α, 0], or 3 o'clock. To use the above formalism the derivatives are needed: y'(s) = \cos \frac{s}{\alpha}\ ; \ x'(s) = \sin \frac{s}{\alpha} \ y''(s) = \frac{1}{\alpha}\sin\frac{s}{\alpha} \ ; \ x''(s) = \frac{1}{\alpha}\cos \frac{s}{\alpha} \ . With these results one can verify that: x'(s)^2 + y'(s)^2 = 1 \ ; \frac{1}{\rho} = y''(s)x'(s)y''(s)x''(s) = \frac{1}{\alpha}\ . The unit vectors also can be found: \mathbf{u}_t(s) = \left[\sin\frac{s}{\alpha},\ \cos\frac{s}{\alpha} \right]\ ; \mathbf{u}_n(s) = \left[\cos\frac{s}{\alpha},\ \sin\frac{s}{\alpha} \right] \ , which serve to show that s = 0 is located at position [ρ, 0] and s = ρπ/2 at [0, ρ], which agrees with the original expressions for x and y. In other words, s is measured counterclockwise around the circle from 3 o'clock. Also, the derivatives of these vectors can be found: \frac{d}{ds}\mathbf{u}_t(s) = \frac{1}{\alpha} \left[\cos\frac{s}{\alpha},\ \sin\frac{s}{\alpha} \right]\ = \frac{1}{\alpha}\mathbf{u}_n(s) \ ; \ \frac{d}{ds}\mathbf{u}_n(s) = \frac{1}{\alpha} \left[\sin\frac{s}{\alpha},\ \cos\frac{s}{\alpha} \right] = \frac{1}{\alpha}\mathbf{u}_t(s) \ . To obtain velocity and acceleration, a timedependence for s is necessary. For counterclockwise motion at variable speed v(t): s(t) = \int_0^t \ dt' \ v(t') \ , where v(t) is the speed and t is time, and s(t=0) = 0. Then: \mathbf{v} = v(t)\mathbf{u}_t(s) \ , \mathbf{a} = \frac{dv}{dt}\mathbf{u}_t(s)+v\frac{d}{dt}\mathbf{ u}_t(s) = \frac{dv}{dt}\mathbf{u}_t(s)v\frac{1}{\alpha}\mathbf{u}_n(s)\frac{ds}{dt} =\frac{dv}{dt}\mathbf{u}_t(s)\frac{v^2}{\alpha}\mathbf{u}_n(s), where it already is established that α = ρ. This acceleration is the standard result for nonuniform circular motion. 

This thread has more than 15 replies. Click here to review the whole thread. 