I think the difference in charge would be negligible if any. You could say the same thing about squrebore carburetors too, generally the secondarys' jets are bigger than the primaries' are. Furthermore, you're presupposing the charge from the carburetor encounters 0 turbulence in the plenum of the intake, where it mixes. Also assuming 0 turbulence, the spreadbore would mix more evenly, considering the two primaries are probably too small to feed all four front slugs at full throttle, so they would draw off the secondaries and mix the charge.
All of this is theoretical. The real answer is this: Not all slugs are drawing charge at the same time, but the carb is feeding non-stop from all four barrels. This means that the two bores that are on their intake stroke at a time are drawing off all four barrels. Your question is assuming that all slugs are drawing at the same time. They're not.
K